0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# The density of a 3M solution of NaCl is 1.25g/ml. Calculate the molality of the solution.

Solution
Verified by Toppr

#### 3 Molar solution means there are 3 moles of NaCl salt in 1 Liter. Molecular weight of NaCl = 58.44. Hence, there are 3×58.44 gms in 1 Litre of water.Density =massvolumeMass of 1 litre of solution = 1.25 gms/ml * 1000 ml = 1, 250 gmsV = volume of water added to make the solution 175.32 gms + 1 gm /ml * V = 1, 250 gm ⟹V=1,074.68mlSo 1,074.68 ml or 1, 074.68 gms of water is mixed with 3 moles of Na Cl to make the 3 M solution. Molality = mass of solute in number of moles / mass of solvent in kg =31.07468kg =2.7915 Molal

35
Similar Questions
Q1
The density of a 3M solution of NaCl is 1.25g/ml. Calculate the molality of the solution.
View Solution
Q2

The density of 3M solution of NaCl is 1.25 g/mL. Calculate molality of the solution.

View Solution
Q3

The molarity of NaNO3 is1 M. The density of solution is 1.25g/ml. Calculate molality of solution. Molar mass of NaNO3= 85g

View Solution
Q4
The density of 3M solution of NaCl is 1.25gml1. The molality of the solution is:
View Solution