Question

The density of a mixture of $O_2$ and $N_2$ NTP is 1.3g/L. Calculate partial pressure of $O_2$.

• A. 0.38 atm
• B. 0.28 atm
• C. 0.48 atm
• D. 0.18 atm

Answer 1

Answer: (B)

Let 1 mol of gas is present.So, 22.4 L will be volume of the mixture

$Density=\frac{mass}{volume}$

Molar Mass of Mixture is $1.3\times 22.4=29.12$ $g/mol$

% of oxygen present in mixture = x

% of nitrogen present in mixture = 1-x

Molar Mass of oxygen and nitrogen are 32 and 28 g/mol respectively

32(x) + 28(1-x) = 29.12

x = 0.28

Partial pressure of $O_2$ is 0.28 atm