The density of CaF-2- -fluorite structure- is 3-18 g cm-3- The length of the side of the unit cell -in pm- is-253344546273

Question

Toppr Admin · Accepted Answer

The correct option is C 546d-zMNA-xD7-VFor flourite structure- z-4 and M-783-18-4-xD7-786-023-xD7-1023-xD7-a3a3-3126-023-xD7-1023-xD7-3-18a3-16-28-xD7-10-x2212-23a-546 pm

The density of $C a F_{2}$ (fluorite structure) is $3.18$ g cm $^{- 3}$ . The length of the side of the unit cell (in pm) is:
$253$
$344$
$546$
$273$

The correct option is C $546$
$d = \frac{z M}{N_{A} \times V}$

For flourite structure, $z = 4$ and $M = 78$

$3.18 = \frac{4 \times 78}{6.023 \times 10^{23} \times a^{3}}$

$a^{3} = \frac{312}{6.023 \times 10^{23} \times 3.18}$

$a^{3} = 16.28 \times 10^{- 23}$

$a = 546$ pm

The density of CaF2 (fluorite structure) is 3.18 g cm−3. The length of the side of the unit cell (in pm) is:253344546273

The correct option is C 546d=zMNA×VFor flourite structure, z=4 and M=783.18=4×786.023×1023×a3a3=3126.023×1023×3.18a3=16.28×10−23a=546 pm

The density of $C a F_{2}$ (fluorite structure) is $3.18$ g cm $^{- 3}$ . The length of the side of the unit cell (in pm) is:
$253$
$344$
$546$
$273$

The correct option is C $546$
$d = \frac{z M}{N_{A} \times V}$

For flourite structure, $z = 4$ and $M = 78$

$3.18 = \frac{4 \times 78}{6.023 \times 10^{23} \times a^{3}}$

$a^{3} = \frac{312}{6.023 \times 10^{23} \times 3.18}$

$a^{3} = 16.28 \times 10^{- 23}$

$a = 546$ pm