The density of ice is $0.921 g c m^{- 3}$ . Calculate the mass of a cubic block of ice which is $76 m m$ on each side.
$4 \times 10^{3} g$
$4 \times 10^{2} g$
$0.04 g$
$49 g$

4 \times 10^{3} g

49 g

4 \times 10^{2} g

0.04 g

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Solution

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Now, 1 $m m$ = 0.1 $c m$
$∴$ 76 $m m$ = 7.6 $c m$
Volume of cube $=$ $(7.6)^{3}$ $=$ 438. 98 $c m^{3}$
Now, mass $=$ density $\times$ volume $=$ 0.921 $\times$ 438.98 $=$ 404 $g$ $=$ $4.04 \times 10^{2} g$

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The density of ice is $0.921 g c m^{- 3}$ . Calculate the mass of a cubic block of ice which is $76 m m$ on each side.
$4 \times 10^{3} g$
$4 \times 10^{2} g$
$0.04 g$
$49 g$

Now, 1 $m m$ = 0.1 $c m$
$∴$ 76 $m m$ = 7.6 $c m$
Volume of cube $=$ $(7.6)^{3}$ $=$ 438. 98 $c m^{3}$
Now, mass $=$ density $\times$ volume $=$ 0.921 $\times$ 438.98 $=$ 404 $g$ $=$ $4.04 \times 10^{2} g$