The density of newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is R, the radius of the planet would be:

The density of newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is R, the radius of the planet would be:

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Q2

The density of newly discovered planet is twice that of the earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is It the radius of the plane would be

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Q3

The density of a newly discovered planet is twice that of the earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is R and the radius of the planet is R′. Then what is the value of RR′?

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Q4

Acceleration due to gravity at surface of a planet is equal to that at surface of the earth and density is 1.5 times that of earth. if radius of earth is R, radius of planet is

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Q5

If the density of a planet is double than that of the earth and the radius is 1.5 times that of the earth, the acceleration due to gravity on the surface of the planet is