The depth which the value of acceleration due to gravity dfrac -1-n- times the value the surface is- -R-radius of the earth-dfrac -R-n-R-dfrac -n-1-n-dfrac -R-n-2-Rleft-dfrac -n-n-1-right-

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The depth at which the value of acceleration due to gravity 1n times the value at the surface is: (R=radius of the earth).RnR(n−1)nRn2R(nn+1)

The depth at which the value of acceleration due to gravity $\frac{1}{n}$ times the value at the surface is: ( $R =$ radius of the earth).
$\frac{R}{n}$
$R \frac{(n - 1)}{n}$
$\frac{R}{n^{2}}$
$R (\frac{n}{n + 1})$