Question

# The depth ′d′ at which the value of acceleration due to gravity becomes 1n times the value at the earth's surface is (R= radius of earth)

A
d=R(nn1)
B
d=R(n1n)
C
d=R(n12n)
D
d=R2(n1n)
Solution
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#### Acceleration due to gravity at a depth d under the earth surface g′=gs(1−dR)Given : g′=gsn∴ gsn=gs(1−dR)Or 1n=(1−dR)⟹ d=R(n−1n)

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