The diagonal of a quadrilateral shaped field is 25m and the perpendiculars dropped on it from the remaining opposite vertices are 8m and 12m. Find the area of the field(in m²).

Question

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m- Find the area of the field-

Toppr Admin · Accepted Answer

Area of quadrilateral - 12 -xD7- Diagonal -xD7- -Sum of the perpendiculars on the diagonal from opposite vertices -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- 12-xD7-24-xD7-8-13-m2 - 252 m2

The diagonal of a quadrilateral shaped field is $24$ m and the perpendiculars dropped on it from the remaining opposite vertices are $8$ m and $13$ m. Find the area of the field.

Area of quadrilateral = $\frac{1}{2}$ $\times$ $D i a g o n a l$ $\times$ [Sum of the perpendiculars on the diagonal from opposite vertices ]

= $\frac{1}{2} \times 24 \times (8 + 13) m^{2}$ = $252$ m $^{2}$

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

Area of quadrilateral = 12 × Diagonal × [Sum of the perpendiculars on the diagonal from opposite vertices ] = 12×24×(8+13)m2 = 252 m2

The diagonal of a quadrilateral shaped field is $24$ m and the perpendiculars dropped on it from the remaining opposite vertices are $8$ m and $13$ m. Find the area of the field.

Area of quadrilateral = $\frac{1}{2}$ $\times$ $D i a g o n a l$ $\times$ [Sum of the perpendiculars on the diagonal from opposite vertices ]

= $\frac{1}{2} \times 24 \times (8 + 13) m^{2}$ = $252$ m $^{2}$