The diagram below shows a cathode ray tube in which the arrow indicates a beam of charged particles approaching an electric field between the plates A and B. State the amount of charge on each particle.

$1.6 \times 10^{- 19} C$
$- 1.6 \times 10^{- 19} C$
0
$- 1.16 \times 10^{- 19} C$

Question

The diagram below shows a cathode ray tube in which the arrow indicates a beam of charged particles approaching an electric field between the plates A and B. State the amount of charge on each particle.

$1.6 \times 10^{- 19} C$
$- 1.6 \times 10^{- 19} C$
0
$- 1.16 \times 10^{- 19} C$

Toppr Admin · Accepted Answer

The beam of charged particles in the cathode ray tube experiment is an electron beam- hence the charge on each particle equals -x2212-1-6-xD7-10-x2212-19-xA0-C

The diagram below shows a cathode ray tube in which the arrow indicates a beam of charged particles approaching an electric field between the plates A and B. State the amount of charge on each particle.1.6×10−19C−1.6×10−19C0−1.16×10−19C

The beam of charged particles in the cathode ray tube experiment is an electron beam, hence the charge on each particle equals −1.6×10−19 C

The diagram below shows a cathode ray tube in which the arrow indicates a beam of charged particles approaching an electric field between the plates A and B. State the amount of charge on each particle.

$1.6 \times 10^{- 19} C$
$- 1.6 \times 10^{- 19} C$
0
$- 1.16 \times 10^{- 19} C$

The beam of charged particles in the cathode ray tube experiment is an electron beam, hence the charge on each particle equals $- 1.6 \times 10^{- 19} C$