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Question

The diagram below shows part of the main scale and vernier scale of a vernier callipers, which is used to measure the diameter of a metal ball. Find the least count and the radius of the ball.
241807_fff0620bba904252aa0d96b959e4125f.png
  1. 0.01cm,2.18cm
  2. 0.02cm,2.18cm
  3. 0.01cm,2.17cm
  4. None of these

A
0.01cm,2.18cm
B
None of these
C
0.01cm,2.17cm
D
0.02cm,2.18cm
Solution
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Least count ,LC=1MSD1VSD
Here 10VSD=9MSD or 1VSD=(9/10)MSD
Thus, LC=(19/10)1MSD=1/10×0.1cm=0.01cm (as 1MSD=0.1cm from diagram)
From diagram, main scale reading, MSR=4.3cm and vernier scale reading, VSR=7 (because division 7 coincide with any line on main scale )
The diameter of the metal ball =MSR+(VSR×LC)=4.3+(7×0.01)=4.37 cm
Radius of the ball =4.37/2=2.185 cm=2.18 cm

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241807_fff0620bba904252aa0d96b959e4125f.png
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