Question

The diameter of a roller is $84cm$ and its length is $120cm$. It takes $500$ complete revolution to move once over to level a playground. Find the area of the playground in $m^2$? [Assume $\pi =\frac{22}{7}$]

Answer 1

Given that:

$d=84cm$

$\Rightarrow$ $r=42$

height $\left(h\right)$ $=120cm$

Hence, the area of the playground leveled in taking complete revolution

$=2\pi rh$

$\left(\pi =\frac{22}{7}=given\right)$

$=2\times \frac{22}{7}\times 42\times 120=31680c{m}^2$

area of playground $=31680\times 500$

$=15840000c{m}^2$

hence, the answer is $=1584m^2$