The diameter of each circle shown in the given figure is 'd' then the area of the square is given by

$3 d^{2}$
$9 d^{2}$
$9 d$
$\frac{3}{4} d^{2}$
$\frac{4}{3} d^{2}$

Question

The diameter of each circle shown in the given figure is -d- then the area of the square is given by 3displaystyle d-2- 9displaystyle d-2-9 ddisplaystyle frac-3-4- d-2-displaystyle frac-4-3- d-2-

Toppr Admin · Accepted Answer

There are 3 circles of diameter -apos-dSo side of the square is 3d and-xA0-Hence area is -xA0- side2-9d2

The diameter of each circle shown in the given figure is 'd' then the area of the square is given by 3d2 9d29d34d243d2

There are 3 circles of diameter 'dSo side of the square is 3d and Hence area is side2=9d2

The diameter of each circle shown in the given figure is 'd' then the area of the square is given by

$3 d^{2}$
$9 d^{2}$
$9 d$
$\frac{3}{4} d^{2}$
$\frac{4}{3} d^{2}$

There are 3 circles of diameter 'd
So side of the square is 3d and
Hence area is $s i d e^{2} = 9 d^{2}$