The diameters of two circles are 32-cm and 24- cm - Find the radius of the circle having its area equal to of the areas of the two given circle-20 - cm41- cm62 - cm52 - cm

Question

Toppr Admin · Accepted Answer

Given-xA0-radii of the two circles-48cm and 13cmSum of areas of given circles-xA0-x3C0-16-2-x3C0-12-2Let- radius of the circle be r-x2234-x3C0-r2-x3C0-16-2-12-2-x21D2-r2-256-144-x21D2-r-x221A-400-xA0-x21D2-r-20cm

The diameters of two circles are $32 c m$ and $24 c m$ . Find the radius of the circle having its area equal to sum of the areas of the two given circle.
$20 c m$
$41 c m$
$62 c m$
$52 c m$

Given, radii of the two circles= $48 c m$ and $13 c m$
Sum of areas of given circles = $π (16)^{2} + π (12)^{2}$
Let, radius of the circle be $r$
$∴ π r^{2} = π (16)^{2} + (12)^{2}$
$\Rightarrow r^{2} = 256 + 144$
$\Rightarrow r = \sqrt{400}$
$\Rightarrow r = 20 c m$

The diameters of two circles are 32cm and 24cm . Find the radius of the circle having its area equal to sum of the areas of the two given circle.20cm41cm62cm52cm

Given, radii of the two circles=48cm and 13cmSum of areas of given circles =π(16)2+π(12)2Let, radius of the circle be r∴πr2=π(16)2+(12)2⇒r2=256+144⇒r=√400 ⇒r=20cm

The diameters of two circles are $32 c m$ and $24 c m$ . Find the radius of the circle having its area equal to sum of the areas of the two given circle.
$20 c m$
$41 c m$
$62 c m$
$52 c m$

Given, radii of the two circles= $48 c m$ and $13 c m$
Sum of areas of given circles = $π (16)^{2} + π (12)^{2}$
Let, radius of the circle be $r$
$∴ π r^{2} = π (16)^{2} + (12)^{2}$
$\Rightarrow r^{2} = 256 + 144$
$\Rightarrow r = \sqrt{400}$
$\Rightarrow r = 20 c m$