The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two.
The metal ion is :
Fe2+
Co2+
Mn2+
Ni2+
A
Fe2+
B
Co2+
C
Mn2+
D
Ni2+
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Solution
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The difference in the number of unpaired electrons of Metal ion in its high-spin and low-spin octahedral complexes is 2.
For the metal Co2+([Ar]3d7) ion, the difference of unpaired electrons is 3−1=2 since the number of unpaired electrons of a metal ion in its high-spin complex is 3 and low-spin complex is 1.
Option B is correct
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