The dimension of the ratio of magnetic flux and the resistance is equal to that of:
inductance
induced emf
charge
current

Question

The dimension of the ratio of magnetic flux and the resistance is equal to that of-inductanceinduced emfchargecurrent

Toppr Admin · Accepted Answer

Dimension of magnetic flux -ML2T-x2212-2A-x2212-1-Dimension of resistance -ML2T-x2212-3A-x2212-2-Therefore-Magneticflux-Resistance-ML2T-x2212-2A-x2212-1-ML2T-x2212-3A-x2212-2-AT-Charge

The dimension of the ratio of magnetic flux and the resistance is equal to that of:inductanceinduced emfchargecurrent

Dimension of magnetic flux =[ML2T−2A−1]Dimension of resistance =ML2T−3A−2]Therefore,[Magneticflux][Resistance]=[ML2T−2A−1][ML2T−3A−2]=[AT]=Charge

The dimension of the ratio of magnetic flux and the resistance is equal to that of:
inductance
induced emf
charge
current

Dimension of magnetic flux $= [M L^{2} T^{- 2} A^{- 1}]$

Dimension of resistance $= M L^{2} T^{- 3} A^{- 2}]$

Therefore,

$\frac{[M a g n e t i c f l u x]}{[R e s i s t a n c e]} = \frac{[M L^{2} T^{- 2} A^{- 1}]}{[M L^{2} T^{- 3} A^{- 2}]} = [A T] = C h a r g e$