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Standard XII
Physics
Dimensional Analysis
Question
The dimensional equation for magnetic flux is:
M
L
2
T
−
2
I
−
2
M
L
2
T
−
2
I
−
1
M
L
−
2
T
−
2
I
−
1
M
L
2
T
−
2
I
2
A
M
L
2
T
−
2
I
2
B
M
L
2
T
−
2
I
−
2
C
M
L
−
2
T
−
2
I
−
1
D
M
L
2
T
−
2
I
−
1
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Solution
Verified by Toppr
Magnetic flux
=
Magnetic Field (B) x Area (A)
B's dimensions
=
Tesla
=
M
I
−
1
T
−
2
A's dimensions
=
L
2
Therefore,
B
A
=
M
L
2
T
−
2
I
−
1
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Similar Questions
Q1
Match the following physical quantities with their respective dimensional formula:
(a) Angular Momentum
(e)
[
M
L
2
T
−
3
]
(b) Impulse
(f)
[
M
L
2
T
−
1
]
(c) Pressure
(g)
[
M
L
T
−
1
]
(d) Power
(h)
[
M
L
−
1
T
−
2
]
View Solution
Q2
Match the physical quantities given in Column I with suitable dimensions expressed in Column
II.
Column I
Column II
a) Angular momentum
g)
M
L
2
T
−
2
b) Latent heat
h)
M
L
2
Q
−
2
c) Torque
i)
M
L
2
T
−
1
d) Capacitane
j)
M
L
3
T
−
1
Q
−
2
e) Inductance
k)
M
−
1
L
−
2
T
2
Q
2
f) Resistivity
l)
L
2
T
−
2
View Solution
Q3
Match the physical quantities given in Column I with suitable dimensions expressed in Column
II.
Column I
Column II
a) Angular momentum
1)
M
−
1
L
3
T
−
2
b) Torque
2)
M
L
T
−
2
c) Gravitational constant
3)
M
L
2
T
−
2
d) Tension
4)
M
L
2
T
−
1
View Solution
Q4
Some physical constants are given in List - I and their dimensional formulae are given in List
- II. Match the following :
List - I
List - II
A) Planck's constant
e)
[
M
L
−
1
T
−
2
]
B) Gravitational constant
f)
[
M
L
1
T
−
1
]
C) Bulk modulus
g)
[
M
L
2
T
−
1
]
D) Linear momentum
h)
[
M
−
1
L
3
T
−
2
]
View Solution
Q5
Match the following two columns:
Column I
Column II
(a) Electrical resistance
(p)
M
L
3
T
−
3
A
−
2
(b) Electrical potential
(q)
M
L
2
T
−
3
A
−
2
(c) Specific resistance
(r)
M
L
2
T
−
3
A
−
1
(d) Specific conductance
(s) None of these
View Solution