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Standard XII
Physics
Dimensional Analysis
Question
The dimensional formula for torque is
M
L
−
1
T
−
1
L
2
T
−
1
M
2
T
−
2
K
−
1
M
L
2
T
−
2
A
M
L
−
1
T
−
1
B
M
2
T
−
2
K
−
1
C
L
2
T
−
1
D
M
L
2
T
−
2
Open in App
Solution
Verified by Toppr
t
=
F
r
=
M
L
T
−
2
L
=
M
L
2
T
−
2
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Similar Questions
Q1
In the ideal gas equation
P
V
=
n
R
T
, dimensional formula of
R
is
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Q2
The dimensional formula for viscosity is
[
M
L
−
1
T
−
1
]
. One poise, i.e, C.G.S. unit of viscosity is:
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Q3
Match the Column I with Column II
Column I
(Units)
Column II
(Dimensional formulae)
(A)
Pa s
(p)
[
M
0
L
2
T
−
2
K
−
1
]
(B)
N m K
−
1
(q)
[
M
L
T
−
3
K
−
1
]
(C)
J kg
−
1
K
−
1
(r)
[
M
L
−
1
T
−
1
]
(D)
W m
−
1
K
−
1
(s)
[
M
L
2
T
−
2
K
−
1
]
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Q4
M
L
−
1
T
−
2
is the dimensional formula of
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Q5
Match List I with List II and select the correct answer using the codes given the lists.
List I
List II
P. Boltzmann Constant
1
.
[
M
L
2
T
−
1
]
Q. Coefficient of viscosity
2
.
[
M
L
−
1
T
−
1
]
R. Plank Constant
3
.
[
M
L
T
−
3
K
−
1
]
S. Thermal conducivity
4
.
[
M
L
2
T
−
2
K
−
1
]
View Solution