The dimensional formula of electric flux is:
$[M^{1} L^{- 3} T^{3} A^{1}]$
$[M^{1} L^{1} T^{- 2}]$
$[M^{1} L^{3} T^{- 3} A^{- 1}]$
$[M^{2} L^{2} T^{- 2} A^{- 2}]$

Question

The dimensional formula of electric flux is:
$[M^{1} L^{- 3} T^{3} A^{1}]$
$[M^{1} L^{1} T^{- 2}]$
$[M^{1} L^{3} T^{- 3} A^{- 1}]$
$[M^{2} L^{2} T^{- 2} A^{- 2}]$

Toppr Admin · Accepted Answer

Electric flux -x3D5-x222B-x2192-E-x2192-sThe dimension of -x3D5- dimension fo E-xD7- dimension of s-x3D5-M1L1T-x2212-2-AT-x2212-1-L2-M1L3T-x2212-3A-x2212-1-

List-I	List-II
A.Spring constant	1. $M^{1} L^{2} T^{- 2}$
B.pascal	2. $M^{0} L^{0} T^{- 1}$
C.hertz	3. $M^{1} L^{0} T^{- 2}$
D.joule	4. $M^{1} L^{- 1} T^{- 2}$

List - I	List - II
A) Spring constant	I) [ $M^{1} L^{2} T^{- 2}$ ]
B) Pascal	II) [ $M^{0} L^{0} T^{- 1}$ ]
C) Hertz	III)[ $M^{1} L^{0} T^{- 2}$ ]
D) Joule	IV) [ $M^{1} L^{- 1} T^{- 2}$ ]

The dimensional formula of electric flux is:[M1L−3T3A1][M1L1T−2][M1L3T−3A−1][M2L2T−2A−2]

Electric flux ϕ=∫→E.→sThe dimension of ϕ= dimension fo E× dimension of s[ϕ]=[M1L1T−2][AT]−1[L2]=[M1L3T−3A−1]

The dimensional formula of electric flux is:
$[M^{1} L^{- 3} T^{3} A^{1}]$
$[M^{1} L^{1} T^{- 2}]$
$[M^{1} L^{3} T^{- 3} A^{- 1}]$
$[M^{2} L^{2} T^{- 2} A^{- 2}]$

Electric flux $ϕ = \int \to E . \to s$
The dimension of $ϕ =$ dimension fo $E \times$ dimension of $s$
$[ϕ] = [M^{1} L^{1} T^{- 2}] {[A T]}^{- 1} [L^{2}] = [M^{1} L^{3} T^{- 3} A^{- 1}]$