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Standard XII
Physics
Dimensional Analysis
Question
The dimensional formula of electric potential is
[
M
L
2
T
−
3
A
−
1
]
[
M
−
1
L
2
T
−
2
A
−
1
]
[
M
−
1
L
2
T
−
2
A
]
[
M
L
2
T
−
2
A
]
A
[
M
L
2
T
−
2
A
]
B
[
M
L
2
T
−
3
A
−
1
]
C
[
M
−
1
L
2
T
−
2
A
]
D
[
M
−
1
L
2
T
−
2
A
−
1
]
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Solution
Verified by Toppr
Electric potential,
V
=
W
q
=
[
M
L
2
T
−
2
]
[
A
T
]
=
[
M
L
2
T
−
3
A
−
1
]
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Similar Questions
Q1
Write the dimensions of
(
a
×
b
)
in the relation
E
=
b
−
x
2
a
t
, where
E
is the energy,
x
is the displacement and
t
is time.
View Solution
Q2
Match the following:
Table-1 Table-2
(
A
)
L
(
P
)
[
M
0
L
0
T
−
2
A
0
]
(
B
)
Magnetic flux
(
Q
)
[
M
L
2
T
−
2
A
−
1
]
(
C
)
L
C
(
R
)
[
M
L
2
T
−
2
A
−
2
]
(
D
)
C
R
2
(
S
)
None
View Solution
Q3
Match the following:
List-1
List-2
a) Angular velocity
e)
M
L
2
T
−
2
b) Angular momentum
f)
M
L
2
T
0
c) Torque
g)
M
0
L
0
T
−
1
d) Moment of inertia
h)
M
L
2
T
−
1
View Solution
Q4
Match the following two columns:
Column I
Column II
A.
Electrical resistance
1.
[
M
L
3
T
−
3
A
−
2
]
B.
Electrical potential
2.
[
M
L
2
T
−
3
A
−
2
]
C.
Specific resistance
3.
[
M
L
2
T
−
3
A
−
1
]
D.
Specific conductance
4.
None of these
View Solution
Q5
Dimensional formula
M L
2
T
−
3
represents
View Solution