The dimensional formula of Planck-s constant is-ML-2T-1-ML-2T-2-MLT-2-ML-0T-2-

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Toppr Admin · Accepted Answer

Energy of photon is given as-xA0-E-h-x3BD-x27F9-h-E-x3BD-Dimension of E-ML2T-x2212-2-Dimension of -x3BD- is -T-x2212-1-Thus the dimension of plank-apos-s constant h is -ML2T-x2212-1-

The dimensional formula of Planck's constant is:
$[M L^{2} T^{- 1}]$
$[M L^{2} T^{- 2}]$
$[M L T^{2}]$
$[M L^{0} T^{2}]$

Energy of photon is given as
$E = h ν$
$⟹ h = \frac{E}{ν}$
Dimension of $E = [M L^{2} T^{- 2}]$
Dimension of $ν$ is $[T^{- 1}]$
Thus the dimension of plank's constant $h$ is $[M L^{2} T^{- 1}]$

The dimensional formula of Planck's constant is:[ML2T−1][ML2T−2][MLT2][ML0T2]

Energy of photon is given as E=hν⟹h=EνDimension of E=[ML2T−2]Dimension of ν is [T−1]Thus the dimension of plank's constant h is [ML2T−1]

The dimensional formula of Planck's constant is:
$[M L^{2} T^{- 1}]$
$[M L^{2} T^{- 2}]$
$[M L T^{2}]$
$[M L^{0} T^{2}]$

Energy of photon is given as
$E = h ν$
$⟹ h = \frac{E}{ν}$
Dimension of $E = [M L^{2} T^{- 2}]$
Dimension of $ν$ is $[T^{- 1}]$
Thus the dimension of plank's constant $h$ is $[M L^{2} T^{- 1}]$