physics

We know that, $Q=CV$ so $CQV =C(CV)V =V_{2}$

So we have to find out only dimension of $V_{2}$

Volatge $V=Ed=QF d$

We know that dimension of force, $[F]=[MLT_{−2}]$, distance $[d]=[L]$ and charge $[Q]=[kT]$ (as charge $=$ current$×$ time)

Now, $[V]=[kT][MLT_{−2}] [L]=[ML_{2}T_{−3}k_{−1}]$

Thus, $[V_{2}]=[M_{2}L_{4}T_{−6}k_{−2}$]

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In general the dimensional formula of a quantity can be written as $[M_{2}HT_{z}].$ Here $x,y,z$ are dimensions.

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