The dimensions of magnetic field in M- L- T and C -coulomb- are given as-MLT-1-C-1-MT-2-C-2-MT-1-C-1-MT-2-C-1-

Question

Toppr Admin · Accepted Answer

Force F acting on charge q moving with velocity v in magnetic field B is given as-xA0-F-qvB thus B-Fqv-x2234-B-F-qv-MLT-x2212-2C-xD7-LT-x2212-1-MT-x2212-1C-x2212-1-

a) Thermal resistance	e) $M T^{- 3} K^{- 4}$
b) Stefan's constant	f) $M L T^{- 3} K^{- 1}$
c) Wein's constant	g) $M^{- 1} L^{- 2} T^{3} K$
d) coefficient of thermal conductivity	h) $M^{o} L K$

The dimensions of magnetic field in $M, L, T$ and $C$ (coulomb) are given as
$[M L T^{- 1} C^{- 1}]$
$[M T^{2} C^{- 2}]$
$[M T^{- 1} C^{- 1}]$
$[M T^{- 2} C^{- 1}]$

Force $F$ acting on charge $q$ moving with velocity $v$ in magnetic field $B$ is given as $F = q v B$ thus $B = \frac{F}{q v}$
$∴ [B] = \frac{[F]}{[q v]} = \frac{M L T^{- 2}}{C \times L T^{- 1}} = [M T^{- 1} C^{- 1}]$

The dimensions of magnetic field in M,L,T and C (coulomb) are given as[MLT−1C−1][MT2C−2][MT−1C−1][MT−2C−1]

Force F acting on charge q moving with velocity v in magnetic field B is given as F=qvB thus B=Fqv∴[B]=[F][qv]=MLT−2C×LT−1=[MT−1C−1]

The dimensions of magnetic field in $M, L, T$ and $C$ (coulomb) are given as
$[M L T^{- 1} C^{- 1}]$
$[M T^{2} C^{- 2}]$
$[M T^{- 1} C^{- 1}]$
$[M T^{- 2} C^{- 1}]$

Force $F$ acting on charge $q$ moving with velocity $v$ in magnetic field $B$ is given as $F = q v B$ thus $B = \frac{F}{q v}$
$∴ [B] = \frac{[F]}{[q v]} = \frac{M L T^{- 2}}{C \times L T^{- 1}} = [M T^{- 1} C^{- 1}]$