The dimensions of of the table is 2 m by 1 m 50 cm- What is its area in square meters-

Question

Toppr Admin · Accepted Answer

Given- Length -l- of the table - 2-xA0-mBreadth -b- of the table - 1-xA0-m-xA0-50-xA0-cm-1-xA0-m-50100-xA0-m-1-5-xA0-m-xA0- -xA0-x2235-1-xA0-cm-1100-xA0-m-xA0-Area - Length -xD7- Breadth- 2-xD7-1-5- 3-xA0-m2Hence- area of the table is 3-xA0-m2-

The dimensions of top of the table is $2 m$ by $1 m 50 c m$ . What is its area in square meters.

Given: Length ( $l$ ) of the table = $2 m$
Breadth ( $b$ ) of the table = $1 m 50 c m = 1 m + \frac{50}{100} m = 1.5 m$ [ $∵ 1 c m = \frac{1}{100} m$ ]
Area = Length $\times$ Breadth
= $2 \times 1.5$
= $3 m^{2}$
Hence, area of the table is $3 m^{2}$ .

The dimensions of top of the table is 2 m by 1 m 50 cm. What is its area in square meters.

Given: Length (l) of the table = 2 mBreadth (b) of the table = 1 m 50 cm=1 m+50100 m=1.5 m [∵1 cm=1100 m] Area = Length × Breadth= 2×1.5= 3 m2Hence, area of the table is 3 m2.

The dimensions of top of the table is $2 m$ by $1 m 50 c m$ . What is its area in square meters.

Given: Length ( $l$ ) of the table = $2 m$
Breadth ( $b$ ) of the table = $1 m 50 c m = 1 m + \frac{50}{100} m = 1.5 m$ [ $∵ 1 c m = \frac{1}{100} m$ ]
Area = Length $\times$ Breadth
= $2 \times 1.5$
= $3 m^{2}$
Hence, area of the table is $3 m^{2}$ .