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Question

The dimensions of universal gravitational constant G are :
  1. [MLT2]
  2. [ML3T2]
  3. [M1L3T2]
  4. [M1LT2]

A
[MLT2]
B
[M1L3T2]
C
[M1LT2]
D
[ML3T2]
Solution
Verified by Toppr

F=Gm1m2r2
Thus, |F|=MLT2=|G|M2L2
or, |G|=M1L3T2

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