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- 20 cm and -25 cm
- 20 cm and +25 cm
- 15 cm and +20 cm
- 15 cm and -20 cm

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Solution

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f1w1+f2w2=0

Also, the effective focal length of the combination will be:

1f=1f1+1f2

Solving these simultaneously and substituting the values, the obtained focal lengths are, fo=15 and fe=−20

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