The displacement equations of two simple harmonic oscillators are given by $x_{1}=A_{1}cosωt$; $x_{2}=A_{2}sin(ωt+6π )$. The phase difference between them is:

A

$30_{∘}$

B

$60_{∘}$

C

$90_{∘}$

D

$120_{∘}$

Medium

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Updated on : 2022-09-05

Solution

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Correct option is B)

$X_{1}=A_{1}cosωt=A_{1}sin(ωt+_{π}/_{2})$ $X_{2}=A_{2}sin(ωt+_{π}/_{6})$ so, phase difference $=2π −6π =3π =60_{0}$