The displacement equations of two simple harmonic oscillators are given by x1=A1cosωt; x2=A2sin(ωt+π6). The phase difference between them is:
30∘
60∘
90∘
120∘
A
90∘
B
30∘
C
60∘
D
120∘
Open in App
Solution
Verified by Toppr
X1=A1cosωt=A1sin(ωt+π/2) X2=A2sin(ωt+π/6) so, phase difference =π2−π6=π3=600
Was this answer helpful?
0
Similar Questions
Q1
The displacement equations of two simple harmonic oscillators are given by x1=A1cosωt; x2=A2sin(ωt+π6). The phase difference between them is:
View Solution
Q2
What is the phase difference between two simple harmonic motions represented by x1=Asin(ωt+π6) and x2=Acos(ωt)?
View Solution
Q3
Two simple harmonic motions are given by: x1=asinωt+acosωt x2=asinωt+a√3cosωt The ratio of the amplitudes of first and second motion and the phase difference between them are respectively:
View Solution
Q4
Two waves are represented by x1=Asin(ωt+π6) and x2=Acosωt then the phase difference between them is :
View Solution
Q5
What will be the displacement equation of the simple harmonic motion obtained by combining the motions? x1=2sinωt, x2=4sin(ωt+π6) and x3=6sin(ωt+π3)