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Question

The displacement of a particle executing SHM at any instant t is x=0.01sin100(t+0.05) then its time period will be
  1. 0.02 s
  2. 0.2 s
  3. 0.06 s
  4. 0.1 s

A
0.1 s
B
0.02 s
C
0.2 s
D
0.06 s
Solution
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x=0.01sin(100t+5)
We have x=Asin(ωt+θ)
On comparing we get
Thus, here ω=100
Thus, T=2πω=2π100=0.06 seconds.

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