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>>Class 11
>>Physics
>>Oscillations
>>Velocity and Acceleration in SHM
>> $The displacement of a particle executing$

Question

The displacement of a particle executing S.H.M. is given by $y = 10 sin (6 t + π / 3)$ in metre and time in seconds. The initial displacement and velocity of the particle are respectively :

A

$25 m$ and $53 m / s$

B

$15 m$ and $53 m / s$

C

$153 m$ and $30 m / s$

D

$103 / 2 m$ and $30 m / s$

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Updated on : 2022-09-05

Solution

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Correct option is D)

Initially $t = 0; y = 10 s i n (\frac{π}{3})$

$= 10 \times \frac{3}{2} = 10 \frac{3}{2} m$

$v = \frac{d y}{d t} = 60 c o s (6 t + \frac{π}{3})$

At $t = 0 \Rightarrow 60 \times c o s \frac{π}{3} = 30 m / s$

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