The displacement of a particle executing S.H.M. is given by y=10sin(6t+π/3) in metre and time in seconds. The initial displacement and velocity of the particle are respectively :
25m and 5√3m/s
15m and 5√3m/s
15√3m and 30m/s
10√3/2m and 30m/s
A
25m and 5√3m/s
B
15m and 5√3m/s
C
15√3m and 30m/s
D
10√3/2m and 30m/s
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Solution
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Initially t=0;y=10sin(π3)
=10×√32=10√32m
v=dydt=60cos(6t+π3)
At t=0⇒60×cosπ3=30m/s
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