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Oscillations
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Velocity and Acceleration in SHM
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The displacement of a particle executing
Question
The displacement of a particle executing S.H.M. is given by
y
=
1
0
sin
(
6
t
+
π
/
3
)
in metre and time in seconds. The initial displacement and velocity of the particle are respectively :
A
2
5
m
and
5
3
m
/
s
B
1
5
m
and
5
3
m
/
s
C
1
5
3
m
and
3
0
m
/
s
D
1
0
3
/
2
m
and
3
0
m
/
s
Medium
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Updated on : 2022-09-05
Solution
Verified by Toppr
Correct option is D)
Initially
t
=
0
;
y
=
1
0
s
i
n
(
3
π
)
=
1
0
×
2
3
=
1
0
2
3
m
v
=
d
t
d
y
=
6
0
c
o
s
(
6
t
+
3
π
)
At
t
=
0
⇒
6
0
×
c
o
s
3
π
=
3
0
m
/
s
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