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Question

The displacement of a particle executing S.H.M. is given by y=10sin(6t+π/3) in metre and time in seconds. The initial displacement and velocity of the particle are respectively :
  1. 25 m and 53 m/s
  2. 15 m and 53 m/s
  3. 153 m and 30 m/s
  4. 103/2 m and 30 m/s

A
25 m and 53 m/s
B
15 m and 53 m/s
C
153 m and 30 m/s
D
103/2 m and 30 m/s
Solution
Verified by Toppr

Initially t=0;y=10sin(π3)

=10×32=1032m

v=dydt=60cos(6t+π3)

At t=060×cosπ3=30m/s

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