The displacement - time graph a particle executing SHM is as shown in figureWhich of the following statement is correct-The velocity of the particle is maximum t - dfrac-3-4- T-The velocity of the particle is maximum t - dfrac-T-2- -The acceleration of the particle is maximum t - dfrac-T-4- -The acceleration of the particle is maximum t - dfrac-3-4- T-

Question

Toppr Admin · Accepted Answer

For the SHM-The displacement of the particle is given by- x-Acos-x3C9-tVelocity- v-dxdt-ddt-Acos-x3C9-t-x2212-A-x3C9-sin-x3C9-t

For the SHM,The displacement of the particle is given by, x=AcosωtVelocity, v=dxdt=ddt(Acosωt)=−Aωsinωt

For the SHM,
The displacement of the particle is given by, $x = A c o s ω t$
Velocity, $v = \frac{d x}{d t} = \frac{d}{d t} (A c o s ω t) = - A ω s i n ω t$