The displacement time graph two particles A and B are straight lines inclined angles of 30o and 600 with the time axis- The ratio of velocities of VA-VB is

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Toppr Admin · Accepted Answer

As velocity v-dxdt-slope of x-x2212-t graph-so VA-VB-slopeA-slopeB-tan300-tan600-1-x221A-3-x221A-3-1-3

The displacement time graph for two particles A and B are straight lines inclined at angles of $30^{o}$ and $60^{0}$ with the time axis. The ratio of velocities of $V_{A} : V_{B}$ is

As velocity $v = \frac{d x}{d t} = s l o p e$ of $x - t$ graph.
so $V_{A} : V_{B} = s l o p e_{A} : s l o p e_{B} = t a n 30^{0} : t a n 60^{0} = \frac{1}{\sqrt{3}} : \sqrt{3} = 1 : 3$

The displacement time graph for two particles A and B are straight lines inclined at angles of 30o and 600 with the time axis. The ratio of velocities of VA:VB is

As velocity v=dxdt=slope of x−t graph.so VA:VB=slopeA:slopeB=tan300:tan600=1√3:√3=1:3

The displacement time graph for two particles A and B are straight lines inclined at angles of $30^{o}$ and $60^{0}$ with the time axis. The ratio of velocities of $V_{A} : V_{B}$ is

As velocity $v = \frac{d x}{d t} = s l o p e$ of $x - t$ graph.
so $V_{A} : V_{B} = s l o p e_{A} : s l o p e_{B} = t a n 30^{0} : t a n 60^{0} = \frac{1}{\sqrt{3}} : \sqrt{3} = 1 : 3$