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# The displacement-time graph of a moving particle with constant acceleration is shown in the figure. The velocity-time graph is given by

A
B
C
D
Solution
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#### Correct option is A. At $$t$$=$$0$$, slope of the $$x-t$$ graph is zero; hence, velocity zero at $$t$$=$$0$$. As time increases, slope increases in negative direction; hence, velocity increases in negative direction. At point '1', slope changes suddenly from negative to positive value; hence, velocity changes suddenly from negative to positive and then velocity starts decreasing and becomes zero at '2'. Option (a) represents all these clearly.

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