The displacement-time graph of a particle executing SHM is shown in the figure. Then
This question has multiple correct options
A
the velocity is maximum at t=T/2
B
the acceleration is maximum at t=T
C
the force is zero at t=3T/4
D
the potential energy equals the oscillation at t=T/2
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Updated on : 2022-09-05
Solution
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Correct options are B) , C) and D)
From the graph, velocity is maximum at t=0,T The acceleration ,dt2d2y is maximum at t=T Force is zero at t=T/2,3T/4 As the interval of max and min displacement is 2T, so the potential energy equals the oscillation at T/2.
