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Question

The displacement-time graph of a particle moving along a straight line is shown in the figure. The acceleration of the particle is:
299771_9ac93524326f42e5a333a39e3a9202e8.png
  1. 0ms2
  2. 4ms2
  3. 8ms2
  4. 12ms2

A
0ms2
B
8ms2
C
4ms2
D
12ms2
Solution
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x= 4t2
v= dxdt=8t
Hence, velocity-time graph is a straight line having slope i.e. tanθ=8
a=dvdt=8m/s2
Hence, acceleration is constant throughout and is equal to 8 m/s2.

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