The pH of 0.1 M solution of cyanic acid (HCNO) is 2.34. Calculate the ionization constant of the acid and its degree of ionization in the solution.
PH=−log[H+]
Hence, [H+]=10−pH
[H+]=10−2.34=4.57×10−3M=[CNO−]
Ka=[H+][CNO−][HCNO]=(4.57×10−3)(4.57×10−3)0.1=2.09×10−4
The degree of dissociation = √Kac=√2.09×10−40.1=4.57×10−2