The dissolution of Al-OH-3 by a solution of NaOH results in the formation of-Al-H-2O-2-OH-4-Al-H-2O-6-OH-3-Al-H-2O-4-OH-2-Al-H-2O-3-OH-3-

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Toppr Admin · Accepted Answer

1- -Al-H2O-4-OH-2-2- Al-OH-3 -xA0-dissolves in NaOH solution to give Al-OH-x2212-4-ion which is supposed to have the octahedral complex species -Al-OH-4-H2O-2-x2212-in aqueous solution-3- Al-OH-3-NaOH-aq-x27F6-Al-OH-4-H2O-2-x2212-aq-NaOH-aq-

The dissolution of Al(OH)3 by a solution of NaOH results in the formation of:[Al(H2O)2(OH)4]−[Al(H2O)6(OH)3]−[Al(H2O)4(OH)2]+[Al(H2O)3(OH)3]+

1. [Al(H2O)4(OH)2]+ 2. Al(OH)3 dissolves in NaOH solution to give Al(OH)−4 ion which is supposed to have the octahedral complex species [Al(OH)4(H2O)2]− in aqueous solution. 3. Al(OH)3+NaOH(aq)⟶[Al(OH)4(H2O)2]−(aq)+NaOH+(aq)

The dissolution of $A l (O H)_{3}$ by a solution of NaOH results in the formation of:
$[A l (H_{2} O)_{2} (O H)_{4}]^{-}$
$[A l (H_{2} O)_{6} (O H)_{3}]^{-}$
$[A l (H_{2} O)_{4} (O H)_{2}]^{+}$
$[A l (H_{2} O)_{3} (O H)_{3}]^{+}$