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Question

The earth's magnetic field at a certain place has a horizontal component of 0.3G and total strength 0.5G. Find angle of dip in tan1.
  1. δ=tan134
  2. δ=tan143
  3. δ=tan135
  4. δ=tan153

A
δ=tan143
B
δ=tan135
C
δ=tan134
D
δ=tan153
Solution
Verified by Toppr

Given that,
Total strength of field B=0.5G,
Horizontal component of the field H=0.3G,
Total strength of field is given by
B=(H2+V2)
where, V is the vertical component of the field.
B2=H2+V2
V2=B2H2=(0.5)2(0.3)2=0.4G
Now, angle of dip is
tanδ=VH=0.40.3=43
δ=tan143

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