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Question

Consider $$12$$ resistors arranged symmetrically in shape of bi-pyramid $$ABCDEF$$. Here $$ABCD$$ is a square. Point $$E$$, paint $$F$$, and center of square are in the same straight line perpendicular to the plane of square. The resistance of each resistor is $$R$$.
The effective resistance between $$A$$ and $$B$$ is

A
$$none\ of\ these$$
B
$$7R/12$$
C
$$5R/12$$
D
$$5R/7$$
Solution
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Correct option is C. $$5R/12$$
Let us remove the resistance between $$A$$ and $$B$$,
then $$E$$ and $$F$$ will be at the same potential, we can draw the remaining as:

$$M$$ is the midpoint of $$DC, M$$ will be at the same pot as $$E$$ and $$F$$.

Now finf $$R_{AB}=5/7R$$.
The resistance which we had removed will be in parallel to it so

$$R_{eq}=\dfrac {R_{AB}R}{R_{AB}+R}=\dfrac {(5/7)RR}{(5/7)R+R}=\dfrac {5}{12}R$$

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