The electric field in a region is directed outward and is proportional to the distance r from the origin. Taking the electric potential at the origin to be zero,
(a) it is uniform in the region
(b) it is proportional to r
(c) it is proportional to r²
(d) it increases as one moves away from the origin

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Toppr Admin · Accepted Answer

Electric field is directly propotional to r- thereforeE-krWe know thatV-x2212-x222B-r0-x2212-x2192-E-x2192-drwhich gives-xA0-V-x2212-kr22 since V at r-0 is 0Hence V is proportional to r2

The electric field in a region is directed outward and is proportional to the distance r from the origin. Taking the electric potential at the origin to be zero,
it is uniform in the region
it is proportional to r
it increases as one goes away from the origion
it is proportional to r $^{2}$

Electric field is directly propotional to $r$ , therefore
$E = k r$
We know that
$V = - \int_{0}^{r} - \to E . \to d r$
which gives
$V = - \frac{k r^{2}}{2}$ since V at $r = 0$ is $0$
Hence V is proportional to $r^{2}$

The electric field in a region is directed outward and is proportional to the distance r from the origin. Taking the electric potential at the origin to be zero,it is uniform in the regionit is proportional to rit increases as one goes away from the origionit is proportional to r2

Electric field is directly propotional to r, thereforeE=krWe know thatV=−∫r0−→E.→drwhich gives V=−kr22 since V at r=0 is 0Hence V is proportional to r2

The electric field in a region is directed outward and is proportional to the distance r from the origin. Taking the electric potential at the origin to be zero,
it is uniform in the region
it is proportional to r
it increases as one goes away from the origion
it is proportional to r $^{2}$

Electric field is directly propotional to $r$ , therefore
$E = k r$
We know that
$V = - \int_{0}^{r} - \to E . \to d r$
which gives
$V = - \frac{k r^{2}}{2}$ since V at $r = 0$ is $0$
Hence V is proportional to $r^{2}$