The electric field strength due to ring of radius R at a distance x from its centre on the axis of ring carrying charge Q is given by E=14πε0Qx(R2+x2)3/2. At what distance from the centre will the electric field be maximum?
The electric field strength due to ring of radius R at a distance x from its centre on the axis of ring carrying charge Q is given by E=14πε0Qx(R2+x2)3/2. At what distance from the centre will the electric field be maximum?
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Q2
The maximum electric field strength E due to a uniformly charged ring of radius r, happens at a distance x, where value of x is (x is measured from the centre of the ring)
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Q3
A point charge q is located at the centre of a thin ring of radius R with uniformly distributed charge −q. Find the magnitude of the electric field strength vector at the point lying on the axis of the ring at a distance x from its centre, if x>>R.
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Q4
A point charge Q is located at centre of a fixed thin ring of radius R with uniformly distributed charge −Q. The magnitude of the electric field strength at the point lying on the axis of the ring at a distance x from the centre is (x>>R)
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Q5
Charge Q is uniformly distributed over a ring of radius r .Electric field at a point on the axis is maximum at a distance x from the centre. x is equal to