The electric potential at a point in free space due to a charge Q coulomb is Q×1011V. The electric field at that point is
12πε0Q×1022Vm−1
4πε0Q×1020Vm−1
4πε0Q×1022Vm−1
12πε0Q×1020Vm−1
A
12πε0Q×1022Vm−1
B
4πε0Q×1020Vm−1
C
4πε0Q×1022Vm−1
D
12πε0Q×1020Vm−1
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Solution
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Here V=Q4πε0r=Q×1011 ∴4πε0r=10−11...(i) Now, E=Q4πε0r2=Q×4πε0(4πε0r)2=Q×4πε0(10−11)2=4πε0Q×1022Vm−1 (Using (i))
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