The electric potential V at any point P(x,y,z) in space is given byV=4x2V. The electric field at the point (1m,2m) is:
−8^i
8^i
−16^i
16^i
A
−8^i
B
8^i
C
−16^i
D
16^i
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Solution
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V=4x2V
→E=−∂V∂x^i−∂V∂y^j−∂V∂z^k
Here, ∂V∂x=8x
and, ∂V∂y=∂V∂z=0
Hence, →E=−8x^i
Given point is (1,2) that is x=1,y=2
Hence, →E=−8^iN/C
Answer-(A)
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