The electric potential V at any point (x, y, z), all in meters in space is given by $V = 4 x^{2}$ volt. The electric field at the point (1, 0, 2) in volt/meter is :

Name: The electric potential V at any point (x, y, z), all in meters in space is given by V = 4x^2 volt. The electric field at the point (1, 0, 2) in volt/meter is :
Uploaded: 2020-01-06
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Answer 1

As $V = 4 x^{2}$ , so the electric field $E = - \frac{d V}{d x} \hat{i} = - 8 x \hat{i}$
At $(1, 0, 2), E = 8 (1) (- \hat{i}) = 8 (- \hat{i})$
Ans: (D)

Answer 2

As

V = 4 x^{2}

, so the electric field

E = - \frac{d V}{d x} \hat{i} = - 8 x \hat{i}

At

(1, 0, 2), E = 8 (1) (- \hat{i}) = 8 (- \hat{i})

Ans: (D)

The electric potential V at any point (x, y, z), all in meters in space is given by $V = 4 x^{2}$ volt. The electric field at the point (1, 0, 2) in volt/meter is :

8 along positive X-axis

16 along negative X-axis

16 along positive X-axis

8 along negative X-axis

As $V = 4 x^{2}$ , so the electric field $E = - \frac{d V}{d x} \hat{i} = - 8 x \hat{i}$
At $(1, 0, 2), E = 8 (1) (- \hat{i}) = 8 (- \hat{i})$
Ans: (D)

$A, B, C, D, P$ and $Q$ are points in uniform electric field. The potentials at these points are $V (A) = 2 v o l t$ . $V (P) = V (B) = V (D) = + 5 v o l t$ . $V (C) = 8 v o l t$ . The electric field at $P$ is:

In a certain region of space, the potential is given by $V = k [2 x^{2} - y^{2} + z^{2}]$ . The electric field at the point $(1, 1, 1)$ has magnitude :

The potential $V$ is varying with x and y as $V = \frac{1}{2} (y^{2} - 4 x)$ volt. The field at $x = 1 m, y = 1 m$ , is :

The potential at a point x (measured in $μ m$ ) due to some charges situated on the x-axis is given by $V (x) = 20 / (x^{2} - 4)$ volt. The electric field $E$ at $x = 4 μ m$ is given by:

The electric field and the electric potential at a point are E and V respectively. Then, the incorrect statements are :

The electric potential V at any point (x, y, z), all in meters in space is given by V=4x2 volt. The electric field at the point (1, 0, 2) in volt/meter is :

8 along positive X-axis

16 along negative X-axis

16 along positive X-axis

8 along negative X-axis

As V=4x2, so the electric fieldE=−dxdV​i^=−8xi^ At (1,0,2),E=8(1)(−i^)=8(−i^) Ans: (D)

A,B,C,D,P and Q are points in uniform electric field. The potentials at these points are V(A)=2 volt. V(P)=V(B)=V(D)=+5 volt. V(C)=8 volt. The electric field at P is:

In a certain region of space, the potential is given by V=k[2x2−y2+z2]. The electric field at the point(1,1,1) has magnitude :

The potential V is varying with x and y as V=21​(y2−4x) volt. The field at x=1m,y=1m, is :

The potential at a point x (measured in μm) due to some charges situated on the x-axis is given by V(x)=20/(x2−4) volt. The electric field E at x=4μm is given by:

The electric field and the electric potential at a point are E and V respectively. Then, the incorrect statements are :

The electric potential V at any point (x, y, z), all in meters in space is given by $V = 4 x^{2}$ volt. The electric field at the point (1, 0, 2) in volt/meter is :

As $V = 4 x^{2}$ , so the electric field $E = - \frac{d V}{d x} \hat{i} = - 8 x \hat{i}$
At $(1, 0, 2), E = 8 (1) (- \hat{i}) = 8 (- \hat{i})$
Ans: (D)

$A, B, C, D, P$ and $Q$ are points in uniform electric field. The potentials at these points are $V (A) = 2 v o l t$ . $V (P) = V (B) = V (D) = + 5 v o l t$ . $V (C) = 8 v o l t$ . The electric field at $P$ is:

In a certain region of space, the potential is given by $V = k [2 x^{2} - y^{2} + z^{2}]$ . The electric field at the point $(1, 1, 1)$ has magnitude :

The potential $V$ is varying with x and y as $V = \frac{1}{2} (y^{2} - 4 x)$ volt. The field at $x = 1 m, y = 1 m$ , is :

The potential at a point x (measured in $μ m$ ) due to some charges situated on the x-axis is given by $V (x) = 20 / (x^{2} - 4)$ volt. The electric field $E$ at $x = 4 μ m$ is given by: