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Question

The electric potential V is given as a function of distance x by V=5x2+10x9. The value of electric field at x=1 is
(All quantities are in SI units.)
  1. 20
  2. 6
  3. 11
  4. 23

A
20
B
23
C
11
D
6
Solution
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V=5x2+10x9

E=Vx^iVy^jVz^k

Now, Vx=10x+10

and Vy=Vz=0

Hence, E=(10x+10)^i

For x=1, E=20^i

Answer-(A)

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