The electron affinity values -kJmol-1- of three halogens X- Y and Z respectively are -349- -333 and -325- Then X- Y and Z respectively are -F-2- Cl-2- and Br-2-Cl-2- F-2- and Br-2-Cl-2- Br-2- and F-2-Br-2- Cl-2- and F-2-

Question

The electron affinity values -kJmol-1- of three halogens X- Y  and Z respectively are -349- -333  and -325- Then X- Y  and Z respectively are -F-2- Cl-2-  and  Br-2-Cl-2- F-2- and Br-2-Cl-2- Br-2- and F-2-Br-2- Cl-2- and F-2-

Toppr Admin · Accepted Answer

Order of EA of halogens is Cl-gt-F-gt-Br-

The electron affinity values (kJmol $^{- 1}$ ) of three halogens $X, Y$ and $Z$ respectively are $- 349$ , $- 333$ and $- 325$ . Then $X, Y$ and $Z$ respectively are :
$F_{2}, C l_{2}$ and $B r_{2}$
$C l_{2}, F_{2}$ and $B r_{2}$
$C l_{2}, B r_{2}$ and $F_{2}$
$B r_{2}, C l_{2}$ and $F_{2}$

Order of $E A$ of halogens is $C l > F > B r$ .

The electron affinity values (kJmol−1) of three halogens X, Y and Z respectively are −349, −333 and −325. Then X, Y and Z respectively are :F2, Cl2 and Br2Cl2, F2 and Br2Cl2, Br2 and F2Br2, Cl2 and F2

Order of EA of halogens is Cl>F>Br.

The electron affinity values (kJmol $^{- 1}$ ) of three halogens $X, Y$ and $Z$ respectively are $- 349$ , $- 333$ and $- 325$ . Then $X, Y$ and $Z$ respectively are :
$F_{2}, C l_{2}$ and $B r_{2}$
$C l_{2}, F_{2}$ and $B r_{2}$
$C l_{2}, B r_{2}$ and $F_{2}$
$B r_{2}, C l_{2}$ and $F_{2}$

Order of $E A$ of halogens is $C l > F > B r$ .