The electronic configuration of an element having atomic number $17$ is:
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4} 4 s^{1}$
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}$
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2} 4 s^{2} 4 p^{1}$
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p_{x}^{2} 3 p_{z}$

Question

The electronic configuration of an element having atomic number $17$ is:
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4} 4 s^{1}$
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}$
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2} 4 s^{2} 4 p^{1}$
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p_{x}^{2} 3 p_{z}$

Toppr Admin · Accepted Answer

If the atomic number is 17- there must be 17 protons and 17 electrons- Starting from the lowest level- we add electrons to each higher level until we have reached 17 electrons-xA0-The electronic configuration is 1s2-xA0-2s22p6-xA0-3s23p5

The electronic configuration of an element having atomic number 17 is:1s2 2s22p6 3s23p4 4s11s2 2s22p6 3s23p51s2 2s22p6 3s23p2 4s24p11s2 2s22p6 3s23p2x3pz

If the atomic number is 17, there must be 17 protons and 17 electrons. Starting from the lowest level, we add electrons to each higher level until we have reached 17 electrons. The electronic configuration is 1s2 2s22p6 3s23p5

The electronic configuration of an element having atomic number $17$ is:
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4} 4 s^{1}$
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}$
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2} 4 s^{2} 4 p^{1}$
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p_{x}^{2} 3 p_{z}$

If the atomic number is 17, there must be 17 protons and 17 electrons. Starting from the lowest level, we add electrons to each higher level until we have reached 17 electrons.
The electronic configuration is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}$