The electronic configuration of Helium is $1 s^{2}$ and of oxygen is:
$1 s^{2}, 2 s^{2}, 2 p^{5}$
$1 s^{2}, 2 s^{2}, 2 p^{4}$
$1 s^{2}, 2 s^{2}, 2 p^{3}$
$1 s^{2}, 2 s^{2}, 2 p^{6}$

Question

The electronic configuration of Helium is 1-s-2- and of oxygen is-1-s-2- 2-s-2- 2-p-5-1-s-2- 2-s-2- 2-p-4-1-s-2- 2-s-2- 2-p-3-1-s-2- 2-s-2- 2-p-6-

Toppr Admin · Accepted Answer

Atomic number of Helium is 2- So electronic configuration is 1s2-Atomic number of Oxygen is 8- So electronic configuration is 1s22s22p4-So answer is B-

The electronic configuration of Helium is 1s2 and of oxygen is:1s2,2s2,2p51s2,2s2,2p41s2,2s2,2p31s2,2s2,2p6

Atomic number of Helium is 2, So electronic configuration is 1s2.Atomic number of Oxygen is 8, So electronic configuration is 1s22s22p4.So answer is B.

The electronic configuration of Helium is $1 s^{2}$ and of oxygen is:
$1 s^{2}, 2 s^{2}, 2 p^{5}$
$1 s^{2}, 2 s^{2}, 2 p^{4}$
$1 s^{2}, 2 s^{2}, 2 p^{3}$
$1 s^{2}, 2 s^{2}, 2 p^{6}$

Atomic number of Helium is 2, So electronic configuration is $1 s^{2}$ .
Atomic number of Oxygen is 8, So electronic configuration is $1 s^{2} 2 s^{2} 2 p^{4}$ .
So answer is B.