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Question

The element that has two unpaired electrons in its $M^{2 +}$ ion form is:

Mn
Cu
Zn
Ti

A

Cu

B

Mn

C

Zn

D

Ti

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Solution

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$T i^{+ 2}$ - $[A r] 3 d^{2}$
$M n^{+ 2}$ - $[A r] 3 d^{5}$
$C u^{+ 2}$ - $[A r] 3 d^{9}$
$Z n^{+ 2}$ - $[A r] 3 d^{10}$
Titanium has two unpaired electrons in its electronic configuration.

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