The e.m.f of a cell is 2.0V and the internal resistance is 0.1Ω. It is connected with a resistance of 3.9Ω. Then potential difference across the cell is :-
A
0.20V
B
1.90V
C
1.95V
D
2.00V
Medium
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Updated on : 2022-09-05
Solution
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Correct option is C)
Current in the circuit is i=3.9+0.12=0.5A
Potential across cell=emf of cell− potential across internal resistance =2−(0.1×0.5)=1.95V