The e-m-f of a cell is 2-0 V and the internal resistance is 0-1 Omega- It is connected with a resistance of 3-9 Omega- Then potential difference across the cell is -0-20V 1-90V 1-95V 2-00V

Question

The e-m-f of a cell is 2-0 V and the internal resistance is 0-1 Omega- It is connected with a resistance of 3-9 Omega- Then potential difference across the cell is -0-20V  1-90V  1-95V  2-00V

Toppr Admin · Accepted Answer

Current in the circuit is i-23-9-0-1-0-5A

The e.m.f of a cell is $2.0 V$ and the internal resistance is $0.1 Ω$ . It is connected with a resistance of $3.9 Ω$ . Then potential difference across the cell is :-
$0.20 V$
$1.90 V$
$1.95 V$
$2.00 V$

Current in the circuit is $i = \frac{2}{3.9 + 0.1} = 0.5 A$

The e.m.f of a cell is 2.0V and the internal resistance is 0.1Ω. It is connected with a resistance of 3.9Ω. Then potential difference across the cell is :-0.20V 1.90V 1.95V 2.00V

Current in the circuit is i=23.9+0.1=0.5A

The e.m.f of a cell is $2.0 V$ and the internal resistance is $0.1 Ω$ . It is connected with a resistance of $3.9 Ω$ . Then potential difference across the cell is :-
$0.20 V$
$1.90 V$
$1.95 V$
$2.00 V$

Current in the circuit is $i = \frac{2}{3.9 + 0.1} = 0.5 A$