0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The emf of a galvanic cell, with electrode potentials of Zn=+0.76 V , is:
  1. +0.34 V
  2. +0.76 V
  3. 1.1 V
  4. +1.1 V

A
+0.34 V
B
+0.76 V
C
+1.1 V
D
1.1 V
Solution
Verified by Toppr

Left electrode : Zn(s)Zn2++2e.
Right electrode : Cu2+(aq)+2eCu(s)

The overall reaction of the cell is the sum of above two reactions:

Zn(s)+Cu2+(aq)Zn2+(aq)+Cu(s)

Emf of the cell,Eocell=Eo(cathode)Eo(anode)

Emf of the cell =0.34V(0.76)V=+1.1V

Hence, option B is correct.

Was this answer helpful?
0
Similar Questions
Q1
The emf of a galvanic cell, with electrode potentials of Zn=+0.76 V , is:
View Solution
Q2
The emf of a galvanic cell constituted with the electrodes Zn2+|Zn(0.76V) and Fe2+|Fe(0.41V) is :
View Solution
Q3
The standard electrode potential of Zn2+|Zn is 0.76 V and that of Cu2+|Cu is 0.34 V. The emf (V) and the free energy change (kJmol1), respectively, for a Daniel cell will be:
View Solution
Q4
The standard reduction potentials of Zn2+|Zn and Cu2+|Cu are -0.76V and +0.34V respectively. What is the cell EMF of the following cell?

Zn|Zn2+(0.05M)||Cu2+(0.005M)|Cu

[RTF=0.059]

View Solution
Q5
The standard electrode potential of the half cells is given below:
Zn2++2eZn;E=0.76V
Fe2++2eFe;E=0.44V
The emf of the cell Fe2+=ZnZn2++Fe
View Solution