Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

The emf of an A.C. source is given by $E = 8 s i n ω t + 6 c o s ω t$ volt. The rms value of emf is
$5 \sqrt{2} V$
$7 \sqrt{2} V$
$10 \sqrt{2} V$
10 V

A

7 \sqrt{2} V

B

5 \sqrt{2} V

C

10 V

D

10 \sqrt{2} V

Open in App

Solution

Verified by Toppr

$E_{r m s} = \sqrt{\frac{1}{T} \int_{0}^{T} E (t)^{2} d t}$

$(E r m s)^{2} = \frac{\int_{0}^{\frac{2 π}{w}} (64 S i n^{2} w t + 36 C o s^{2} w t + 96 S i n w t C o s w t) d t}{\int_{0}^{\frac{2 π}{w}} d t}$

Was this answer helpful?

0

Similar Questions

Q1

The emf of an A.C. source is given by

E = 8 s i n ω t + 6 c o s ω t

volt. The rms value of emf is

View Solution

Q2

Determine the rms value of the emf given by:

E

(in volt)

= 8 sin (ω t) + 6 sin (2 ω t)

View Solution

Q3

What is the total emf, when three cells of emfs

2 V

,

2 V

,

2 V

connected in parallel?

View Solution

Q4

The rms value of alternating emf

E = (8 sin ω t + 6 sin 2 ω t) V

is

View Solution

Q5

The peak value of an alternating emf is given by

E = E_{0} c o s (w t)

is 10 volt and its frequency is 50 Hz. At a time

t = (\frac{1}{600})

second, the instantaneous value of the emf is:

View Solution